0.2
0.15
0.1
0.05
0
–0.05
–0.1
–0.15
–0.2
50mV
G = +1
RL = 18.75⍀
VO = 0.2V p-p
20ns
Figure 21. Small-Signal Pulse Response; G = +1
0.2
0.15
0.1
0.05
0
–0.05
–0.1
–0.15
–0.2
G = +2, –1
RL = 18.75⍀
VO = 0.2V p-p
50mV
20ns
Figure 22. Small-Signal Pulse Response; G = +2, –1
100
10
1
10
100
1k
10k
100k
1M
10M
FREQUENCY – Hz
Figure 23. Input Voltage Noise vs. Frequency
5
4
3
2
1
0
–1
–2
–3
–4
1V
–5
AD8010
G = +1
RL = 18.75⍀
VO = 4V p-p
20ns
Figure 24. Large-Signal Pulse Response; G = +1
4
3
2
1
0
–1
–2
–3
–4
1V
G = +2, –1
RL = 18.75⍀
VO = 4V p-p
20ns
Figure 25. Large-Signal Pulse Response; G = +2, –1
1000
100
INVERTING CURRENT
10
NONINVERTING CURRENT
1
10
100
1k
10k
100k
FREQUENCY – Hz
1M
10M
Figure 26. Input Current Noise vs. Frequency
REV. B
–7–