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MAX767EAP(1994) 데이터 시트보기 (PDF) - Maxim Integrated

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MAX767EAP Datasheet PDF : 20 Pages
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5V-to-3.3V, Synchronous, Step-Down
Power-Supply Controller
Place R1 as close as possible to the MAX767, prefer-
ably less than 10mm. Run the traces at minimum spac-
ing from one another. If they are longer than 20mm,
bypass CS to FB with a 1nF capacitor placed as close
as possible to these pins. The wiring layout for these
traces is critical for stable, low-ripple outputs (see
Layout and Grounding section).
Input Filter Capacitor, C1
Use at least 6µF per watt of output power for C1. If the
5V input is some distance away or comes through a PC
bus, greater capacitance may be desirable to improve
the load-transient response. Use a low-ESR capacitor
located no further than 10mm from the MOSFET switch
(N1) to prevent ringing. The ripple current rating must
be at least IRMS = 0.5 x IOUT. For high-current applica-
tions, two or more capacitors in parallel may be needed
to meet these requirements.
The ESR of C1 is effectively in series with the input. The
resistive dissipation of C1, IRMS2 x ESRC1, can signifi-
cantly impact the circuit’s efficiency.
Output Filter Capacitor, C2
The output filter capacitor determines the loop stability,
output voltage ripple, and output load-transient
response.
Stability
To ensure stability, stay above the minimum capaci-
tance value and below the maximum ESR value. These
values are:
C2 > —3— µF
R1
and
ESRC2 < R1
Be sure to satisfy both these requirements. To achieve
the low ESR required, it may be appropriate to parallel
two or more capacitors and/or use a total capacitance
2 or 3 times larger than the calculated minimum.
Output Ripple
The output ripple in continuous-conduction mode is:
VOUT(RPL) = IOUT(max) x LIR x
(ESRC2
+
————1 ———)
2 x π x f x C2
where f is the switching frequency (200kHz or 300kHz).
In idle-mode, the ripple has a capacitive and a resistive
component:
.
VOUT(RPL) (C) = __0_._0_0_0_4__x_L___ x 0.89 Volts
R12 x C2
VOUT(RPL) (R) = 0_._0_2__x_E__S_R_C_2__
R1
The total ripple, VOUT(RPL), can be approximated as
follows:
if
VOUT(RPL) (R) < 0.5 VOUT(RPL) (C)
then
VOUT(RPL) = VOUT(RPL)(C)
otherwise
VOUT(RPL) = 0.5 VOUT(RPL) (C) +
VOUT(RPL) (R)
Load-Transient Performance
In response to a large step increase in load current, the
output voltage will sag for several microseconds unless
C2 is increased beyond the values that satisfy the
above requirements. Note that an increase in capaci-
tance is all that’s required to improve the transient
response, and that the ESR requirements don’t change.
Therefore, the added capacitance can be supplied by
an additional low-cost bulk capacitor in parallel with the
normal low-ESR switching-regulator capacitor. The
equation for voltage sag under a step load change is:
VSAG = ___________I_S_T_E_P_2_x__L_____________
2 x C2 x (VIN(min) x DMAX - 3.3V)
where DMAX is the maximum duty cycle. Higher duty
cycles are possible when the oscillator frequency is
reduced to 200kHz, since fixed propagation delays
through the PWM comparator become a lesser part of
the whole period. The tested worst-case limit for DMAX
is 92% at 200kHz or 89% at 300kHz. Lower inductance
values can reduce the filter capacitance requirement,
but only at the expense of increased output ripple (due
to higher peak currents).
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