PA12 데이터 시트보기 (PDF) - Apex Microtechnology
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PA12 Datasheet PDF : 5 Pages
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PA12 • PA12A
GENERAL
Please read Application Note 1 "General Operating Con-
siderations" which covers stability, supplies, heat sinking,
mounting, current limit, SOA interpretation, and specification
interpretation. Visit www.apexanalog.com for design tools that
help automate tasks such as calculations for stability, internal
power dissipation, current limit; heat sink selection; Apex Mi-
crotechnology’s complete Application Notes library; Technical
Seminar Workbook; and Evaluation Kits.
SAFE OPERATING AREA (SOA)
The output stage of most power amplifiers has three distinct
limitations:
1. The current handling capability of the transistor geometry
and the wire bonds.
2. The second breakdown effect which occurs whenever the
simultaneous collector current and collector-emitter voltage
exceeds specified limits.
3. The junction temperature of the output transistors.
15
10
6.0 THERMAL
4.0
3.0
2.0
1.0
SOA
T
C
=
25°C
T
C
=
85°C
T
C
=
125°C
.6
.4
SECOND BREAKDOWN
.3
10
20
30 40 50 70 100
SUPPLY TO OUTPUT DIFFERENTIAL VOLTAGE, VS - VO (V)
The SOA curves combine the effect of all limits for this Power
Op Amp. For a given application, the direction and magnitude
of the output current should be calculated or measured and
checked against the SOA curves. This is simple for resistive
loads but more complex for reactive and EMF generating
loads. However, the following guidelines may save extensive
analytical efforts.
1. Capacitive and dynamic* inductive loads up to the following
maximum are safe with the current limits set as specified.
CAPACITIVE LOAD
INDUCTIVE LOAD
±VS
ILIM = 5A
ILIM = 10A ILIM = 5A ILIM = 10A
50V
200µF
125µF
5mH
2.0mH
40V
500µF
350µF 15mH
3.0mH
35V
2.0mF
850µF 50mH
5.0mH
30V
7.0mF
2.5mF 150mH
10mH
25V
25mF
10mF 500mH
20mH
20V
60mF
20mF 1,000mH 30mH
15V
150mF
60mF 2,500mH 50mH
*If the inductive load is driven near steady state conditions,
allowing the output voltage to drop more than 8V below the
supply rail with ILIM = 15A or 25V below the supply rail with ILIM
= 5A while the amplifier is current limiting, the inductor must
be capacitively coupled or the current limit must be lowered
to meet SOA criteria.
2. The amplifier can handle any EMF generating or reactive
load and short circuits to the supply rail or common if the
current limits are set as follows at TC = 25°C:
SHORT TO ±VS
SHORT TO
±VS
C, L, OR EMF LOAD
COMMON
50V
.30A
2.4A
40V
.58A
2.9A
35V
.87A
3.7A
30V
1.5A
4.1A
25V
2.4A
4.9A
20V
2.9A
6.3A
15V
4.2A
8.0A
These simplified limits may be exceeded with further analysis
using the operating conditions for a specific application.
CURRENT LIMITING
Refer to Application Note 9, "Current Limiting", for details of
both fixed and foldover current limit operation. Visit the Apex
Microtechnology web site at www.apexanalog.com for a copy
of the Power Design spreadsheet (Excel) which plots current
limits vs. steady state SOA. Beware that current limit should
be thought of as a +/–20% function initially and varies about
2:1 over the range of –55°C to 125°C.
For fixed current limit, leave pin 7 open and use equations
1 and 2.
RCL = 0.65/LCL
(1)
ICL = 0.65/RCL
(2)
Where:
ICL is the current limit in amperes.
RCL is the current limit resistor in ohms.
For certain applications, foldover current limit adds a slope
to the current limit which allows more power to be delivered
to the load without violating the SOA. For maximum foldover
slope, ground pin 7 and use equations 3 and 4.
0.65 + (Vo * 0.014)
ICL =
RCL
(3)
RCL =
0.65 + (Vo * 0.014)
ICL
(4)
Where:
Vo is the output voltage in volts.
Most designers start with either equation 1 to set RCL for the
desired current at 0v out, or with equation 4 to set RCL at the
maximum output voltage. Equation 3 should then be used to
plot the resulting foldover limits on the SOA graph. If equa-
tion 3 results in a negative current limit, foldover slope must
be reduced. This can happen when the output voltage is the
opposite polarity of the supply conducting the current.
In applications where a reduced foldover slope is desired,
this can be achieved by adding a resistor (RFO) between pin
7 and ground. Use equations 4 and 5 with this new resistor
in the circuit.
0.65 + Vo * 0.14
ICL =
10.14 + RFO
RCL
(5)
0.65 + Vo * 0.14
RCL =
10.14 + RFO
ICL
(6)
Where:
RFO is in K ohms.
4
PA12U
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