LT1956 데이터 시트보기 (PDF) - Linear Technology

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LT1956

High Voltage, 1.5A, 500kHz Step-Down Switching Regulators

Linear Technology 

LT1956/LT1956-5

APPLICATIO S I FOR ATIO

iron cores are forgiving because they saturate softly,

whereas ferrite cores saturate abruptly. Other core mate-

rials fall somewhere in between. The following formula

assumes continuous mode of operation, but errs only

slightly on the high side for discontinuous mode, so it can

be used for all conditions.

( ) IPEAK

= IOUT

+ ILP-P

2

= IOUT

+

VOUT VIN – VOUT

2 • VIN • f • L

EMI

Decide if the design can tolerate an “open” core geometry

like a rod or barrel, which have high magnetic field

radiation, or whether it needs a closed core like a toroid to

prevent EMI problems. This is a tough decision because

the rods or barrels are temptingly cheap and small and

there are no helpful guidelines to calculate when the

magnetic field radiation will be a problem.

Additional Considerations

After making an initial choice, consider additional factors

such as core losses and second sourcing, etc. Use the

experts in Linear Technology’s Applications department if

you feel uncertain about the final choice. They have

experience with a wide range of inductor types and can tell

you about the latest developments in low profile, surface

mounting, etc.

MAXIMUM OUTPUT LOAD CURRENT

Maximum load current for a buck converter is limited by

the maximum switch current rating (IP). The current rating

for the LT1956 is 1.5A. Unlike most current mode convert-

ers, the LT1956 maximum switch current limit does not

fall off at high duty cycles. Most current mode converters

suffer a drop off of peak switch current for duty cycles

above 50%. This is due to the effects of slope compensa-

tion required to prevent subharmonic oscillations in cur-

rent mode converters. (For detailed analysis, see Applica-

tion Note 19.)

The LT1956 is able to maintain peak switch current limit

over the full duty cycle range by using patented circuitry to

cancel the effects of slope compensation on peak switch

current without affecting the frequency compensation it

provides.

Maximum load current would be equal to maximum

switch current for an infinitely large inductor, but with

finite inductor size, maximum load current is reduced by

one half of peak-to-peak inductor current (ILP-P). The

following formula assumes continuous mode operation,

implying that the term on the right is less than one half

of␣ IP.

IOUT(MAX) Continuous Mode

= IP

–

ILP-P

2

= IP

–

(VOUT

+ VF )(VIN – VOUT

(2)(VIN)(f)(L)

– VF )

For VOUT = 5V, VIN(MAX) = 8V, VF(DI) = 0.63V, f = 500kHz

and L = 10µH:

( )( ) IOUT(MAX)

=

1.5

–

(5 +

(2)(8)

0.63)(8 –

500 •103

5 – 0.63)

10 •10–6

= 1.5 – 0.17 = 1.33A

Note that there is less load current available at the higher

input voltage because inductor ripple current increases. At

VIN = 15V and using the same set of conditions:

( )( ) IOUT(MAX)

=

1.5

–

(5 + 0.63)(15 –

(2)(15) 500 •103

5 – 0.63)

10 •10–6

= 1.5 – 0.35 = 1.15A

To calculate peak switch current with a given set of

conditions, use:

ISW(PEAK)

=

IOUT

+

ILP-P

2

=

IOUT

+

(VOUT

+ VF )(VIN – VOUT

(2)(VIN)(f)(L)

–

VF )

Reduced Inductor Value and Discontinuous Mode

If the smallest inductor value is of the most importance to

a converter design, in order to reduce inductor size/cost,

discontinuous mode may yield the smallest inductor

1956f

11

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