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LT3580I 데이터 시트보기 (PDF) - Linear Technology

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LT3580I Datasheet PDF : 28 Pages
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LT3580
APPLICATIONS INFORMATION
Compensation—Theory
Like all other current mode switching regulators, the
LT3580 needs to be compensated for stable and efficient
operation. Two feedback loops are used in the LT3580—
a fast current loop which does not require compensation,
and a slower voltage loop which does. Standard bode plot
analysis can be used to understand and adjust the voltage
feedback loop.
As with any feedback loop, identifying the gain and phase
contribution of the various elements in the loop is critical.
Figure 4 shows the key equivalent elements of a boost
converter. Because of the fast current control loop, the
power stage of the IC, inductor and diode have been replaced
by a combination of the equivalent transconductance
amplifier gmp and the current controlled current source
(which converts IVIN to ηVIN/VOUT • IVIN). gmp acts as
a current source where the peak input current, IVIN, is
proportional to the VC voltage. η is the efficiency of the
switching regulator, and is typically about 88%.
Note that the maximum output currents of gmp and gma are
finite. The limits for gmp are in the Electrical Characteristics
section (switch current limit), and gma is nominally limited
to about ±12μA.
gmp
+
VC
gma
CF RC RO
CC
IVIN
H • VIN
VOUT
• IVIN
CPL
1.215V
REFERENCE
R2
FB
R2
VOUT
RESR
RL
COUT
R1
3580 F04
CC: COMPENSATION CAPACITOR
COUT: OUTPUT CAPACITOR
CPL: PHASE LEAD CAPACITOR
CF: HIGH FREQUENCY FILTER CAPACITOR
gma: TRANSCONDUCTANCE AMPLIFIER INSIDE IC
gmp: POWER STAGE TRANSCONDUCTANCE AMPLIFIER
RC: COMPENSATION RESISTOR
RL: OUTPUT RESISTANCE DEFINED AS VOUT DIVIDED BY ILOAD(MAX)
RO: OUTPUT RESISTANCE OF gma
R1, R2: FEEDBACK RESISTOR DIVIDER NETWORK
RESR: OUTPUT CAPACITOR ESR
Figure 4. Boost Converter Equivalent Model
From Figure 4, the DC gain, poles and zeros can be cal-
culated as follows:
Output Pole: P1=
2
2 • π • RL • COUT
Error Amp Pole: P2 =
1
2 • π ⎡⎣RO + RC ⎤⎦ • CC
Error Amp Zero: Z1=
1
2 • π • RC • CC
DC Gain:
(Breaking Loop at FB Pin)
ADC
= AOL(0) =
VC
VFB
IVIN
VC
VOUT
IVIN
VFB
VOUT
=
) (gma • R0
• gmp
⎝⎜ η
VIN
VOUT
RL
2
⎠⎟
0.5R2
R1+ 0.5R2
ESR Zero: Z2 =
1
2 • π • RESR • COUT
RHP Zero:
Z3
=
2
VIN2 • RL
π • VOUT2
L
High Frequency Pole: P3 > fS
3
Phase Lead Zero: Z4 =
1
2 • π • R1• CPL
Phase Lead Pole: P4 =
1
R1• R2
2
π
R1+
2
R2
• CPL
2
Error Amp Filter Pole:
P5
=
1
2 • π RC •RO
RC +RO
• CF
,CF
< CC
10
The current mode zero (Z3) is a right-half plane zero
which can be an issue in feedback control design, but is
manageable with proper external component selection.
3580fg
11

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